Here's the problem
write arccos(x/2) in algebraic form (hint: use a triangle)
Thank you!
Here's the problem
write arccos(x/2) in algebraic form (hint: use a triangle)
Thank you!
i*({<|}0.467)/4
Well, it's been a while since I've taken a math course, so I'm not really sure what "algebraic form" means off the top of my head.
If you're looking at a right triangle with one angle being theta, then cos(theta) = adjacent/hypotenuse. That means arccos(adjacent/hypotenuse) = theta. So the side adjacent to theta is x, the hypotenuse is 2 and the opposite side is sqrt(4 - x^2).
I'm not sure if that helps since I don't really know what the question wants as an answer.
Is it possible you misstated the question, and it's actually something like sin(arccos(x/2))?Originally Posted by gt_killa
Oh god school's back in session. Here come the 'I can't do my homework do it for me /bg/' threads again.
-1/sqrt(4-x^2)
That's definitely an answer to a question, but it isn't the question that the OP asked.Originally Posted by souleman
Look on the bright side, it's more opportunities to throw in variations of divided by zero!Originally Posted by Correction
isn't this is the derivative of arccos, d/dx (arccos(x/2)) ?Originally Posted by divisortheory
OP then just try to intergrate this function then , have fun >.>
Close, it's half of the derivative. it's also -csc(arccos(x/2))/2.Originally Posted by Osede
But since the OP's question doesn't make any sense really, it's hard to know what he was asking.
meh. i'm feel bad i'm master grad but can't solve the problem lol
Don't feel bad, problem doesn't make any sense lol.Originally Posted by Osede
I think your close to what it should be though, i finished my calc last quarter, so it's fuzzy but if memory serves I remember a section of something involving the sin(arccos(x/2))? or something, I remember the example using a triangle too...if I wasnt at work i'd so whip out my old notebook...lol
Even if that's it though, is it sin(arccos(x/2)), tan(arccos(x/2)), sec(arccos(x/2)), csc(arccos(x/2)), or cot(arccos(x/2))?
Sorry, I couldn't figure out how to write geometric shape in an algebraic form.
Maybe they were thinking in asking this instead?
cos (x/2) = sqrt((1+cos(x))/2)
or the more obvious
arccos (x/2) = pi/2 - arcsin (x/2)
or make some work with Euler formulas, but I assume you are not being teached those anytime soon and doubt that those lead to anything special with x/2.
I copied the question exactly from the book word for word D:...Didn't understand what they want to as an answer so I'm just asking for help here. Thank you for trying for so far !
Can't arccos be expressed as something involving e^x, with no explicitly trigonometric terms?
This might help: what class is it for?
Yea, what class was it for? The hint made me think it was a sin(arccos) problem or something similar, which would mean probably Trig I or something like thatOriginally Posted by Charla
It's Calculus 1 ;