Solve this

[Foof]

http://i12.tinypic.com/73dnr6d.jpg
TIPS

(a) each puzzle leads you to figuring out the next one
(b) some steps involve a chain of ciphers
(c) if using text with spaces (i.e. as a key), ignore the spaces
(d) there are red herrings & tricky riddles
(e) share your partial solutions because this may require cooperation

From a post on the WOW boards (though I'm sure it originates elsewhere). I personally am not very good at this, but it's pretty cool what people come up with.

Recap (so far) of what people have come up with is here . Sort of spoilers for the first image, obviously

[Tricen]

/pass

[Faris]

cmon man, that looks scary, lol.

EDIT::
666 posts, THE END IS NEAR!

[Foof]

cmon man, that looks scary, lol.

EDIT::
666 posts, THE END IS NEAR!

Yea, it does...which makes it so interesting Pretty much all of the answers found so far have been way over my head, so I'm really hoping to see some people familiar with cyphers/codes/encriptions/whatever here

[MisterBob]

The first one is very easy if you are familiar with this type of stuff. (Hint, look up ROT47 on the Wikipidia)

As for the rest...maybe tomorrow

[octopus]

do we get gil if we solve it? Seeing that you get 1000g in WoW if you do (I have no idea if that is a lot)

[Naramaska]

Oh gdi.


Now i'm going to waste all afternoon on this -_-

[Mizango]

Let's not, but let's say we did k?

[Serif]

do we get gil if we solve it? Seeing that you get 1000g in WoW if you do (I have no idea if that is a lot)

So we are basically helping some one get 1000G, which he could possibly turn around for about $200 if he RMTs it?

Passsssssssssssssss

[Exoduso]

This looks disturbing.

[Mizango]

Absolutely diabolical!

No seriously, what's the answer?

[Turambar]

It obviously says "Call Foof for a good time". I'll pass on that though.

[Remyo]

6 section is star wars alphabet translated is:

tmt yutylt zjcu vfelt
tmxy xv nggd qtglzxe q
pqpevr belttt.

gibberish but the last line looks like paper belt. idk last section looks like morse?

[Shuemue]

It obviously says "Call Foof for a good time". I'll pass on that though.

iirc she's quite pretty and no longer jailbait.

[Charla]

Section 5 is pretty obviously wingdings, but without the first 4 it probably wouldn't mean anything.

[Khamsin]

It obviously says "Call Foof for a good time". I'll pass on that though.

iirc she's quite pretty and no longer jailbait.

Unlike Poof.

[aurik]

http://imgs.xkcd.com/comics/nerd_sniping.png

[Bwelch]

It's the first paragraph in Moby-Dick.

I don't know. lol

[Tricen]

http://imgs.xkcd.com/comics/nerd_sniping.png

Flawless.

[Neosutra]

http://imgs.xkcd.com/comics/nerd_sniping.png

Given two adjacent vertices p and q, the resistance across the edge from p to q is the voltage drop along the edge when a 1 amp current is injected at p and withdrawn at q. Whether or not p and q are adjacent, the unit current flow from p to q can be written as the superposition of the unit current flow from p out to infnity and the unit current flow from infinity into q.

By symmetry, in the unit current flow from p to infinity, the flow out of p is distributed equally among the 2d edges going out of p, so the flow along any one of them is 1/2d amps. Similarly, in the unit current flow into q, the flow along each edge coming into q is 1/2d . If p and q are adjacent, when the two flows are superimposed the flow along the edge from p to q is 2*1/(2d) = 1/d.

But since this edge has resistance 1 ohm, the voltage drop along it is also 1/d, so the efective resistance between p and q is 1/d.

I'll watch out for semi trucks on the way home from work.