Are you assuming the multihits weapon chances don't enter into the SUM(D+T)=1 + "mutually exclusive" ?
That's THE info i voluntarily omitted since it is confusing me so much about * or + or nothing at all into the formulas...
Anyways, i just tested your proposition :
a)1st test
D=T=0
Xmax=3 (Ridill used)
Code:
P(single)=(1-(3-1)/3)*(1-0-0) = 1/3
P(double) = (1/3)*(1-0-0) + 0 = 1/3
P(triple) = (1/3)*(1-0-0) + 0 = 1/3
Ptotal=100%
Unless i made an error, that makes indeed a 3:3:3 for ratios 1:2:3attacks (i don't understand how and why you said 3:5:2)
b)2nd test
D=9%
T=0
Xmax=3 (Ridill used)
Code:
P(single)=(1-(3-1)/3)*(1-0.09-0) = 30.333%
P(double) = (1/3)*(1-0.09-0) + 0.09 = 39.333%
P(triple) = (1/3)*(1-0.09-0) + 0 = 30.333%
Ptotal=100%
Those results sound totally logical to me compared to 1st test 
c)3rd test
D=T=0
Xmax=8 (Kraken Club used)
Code:
P(single)=(1-(8-1)/8)*(1-0-0) = 12.50%
P(double) = (1/8)*(1-0-0) + 0 = 12.50%
P(triple) = (1/8)*(1-0-0) + 0 = 12.50%
P(4) = (1/8)*(1-0-0) = 12.50%
P(5) = (1/8)*(1-0-0) = 12.50%
P(6) = (1/8)*(1-0-0) = 12.50%
P(7) = (1/8)*(1-0-0) = 12.50%
P(8) = (1/8)*(1-0-0) = 12.50%
Ptotal=100%
Then i put D=T=50% (that's what were making all my attempts fail when coupled with a multihits weapon, since total were getting either above or below 100%)
Let's see :
Code:
P(single)=(1-(8-1)/8)*(1-0.5-0.5) = 0%
P(double) = (1/8)*(1-0.5-0.5) + 0.5 = 50%
P(triple) = (1/8)*(1-0.5-0.5) + 0.5 = 50%
P(4) = (1/8)*(1-0.5-0.5) = 0%
P(5) = (1/8)*(1-0.5-0.5) = 0%
P(6) = (1/8)*(1-0.5-0.5) = 0%
P(7) = (1/8)*(1-0.5-0.5) = 0%
P(8) = (1/8)*(1-0.5-0.5) = 0%
Ptotal=100%
There we can see Psingle = 0% and all hits from Kclub only are nulled... doesnot make sense... and that was assuming Sum(D+T)=1 like you said.
Those results basically mean that someone using a Kclub and having very high Double AND Triple Attack rates would ALWAYS have 2 or 3 hits ONLY occuring in each round... I'm not sure if it's realistic ?